Solve the quadratic equation.

(x + 3)2 = 64
A) x = 5 or -11
B) x = 11 or -5
C) x = ± 3
D) x = ± 11

Question

01-04-2017
Mathematics

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Solve the quadratic equation.

(x + 3)2 = 64
A) x = 5 or -11
B) x = 11 or -5
C) x = ± 3
D) x = ± 11

Respuesta :

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All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

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Luv2Teach Luv2Teach · Answer 1 · 2017-04-05T02:31:06+02:00

Luv2Teach Luv2Teach

05-04-2017

The answer is A. You start by "undoing" the square on the left by taking the square root of both sides, which gives you, simplified version here, x+3=+/-8. Move the 3 over by subtraction to get 2 different values for x now: x=8-3 which is 5, or x= -8-3 which is -11.

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Solve the quadratic equation. (x + 3)2 = 64 A) x = 5 or -11 B) x = 11 or -5 C) x = ± 3 D) x = ± 11

Respuesta :

Otras preguntas

Solve the quadratic equation.

(x + 3)2 = 64
A) x = 5 or -11
B) x = 11 or -5
C) x = ± 3
D) x = ± 11