Assuming that the smallest measurable wavelength in an experiment is 0. 450 fm , what is the maximum mass of an object traveling at 479 m⋅s−1 for which the de broglie wavelength is observable?

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bhoopendrasisodiya34 bhoopendrasisodiya34 · Answer 1 · 2022-05-12T14:11:02+02:00

The maximum mass of an object traveling at 479 m⋅s−1 for which the de broglie wavelength is observable, is 3.82×10⁻²⁷ kg.

To find the wavelength of a wave, Broglie given an equation. This equation for wavelength is,

[tex]\lambda=\dfrac{h}{mv}[/tex]

Here, (h) is the planks constant, m is mass and (v) is the velocity.

Assuming that the smallest measurable wavelength in an experiment is 0. 450 fm. The speed of the object is 479 m⋅s−1.

Put the values in the formula,

[tex]\lambda=\dfrac{h}{mv}\\ 0.450\times10^{-15}=\dfrac{6.63\times10^{-34}}{m\times479}\\m=3.07\times10^{-21}\rm \;kg[/tex]

Thus, the maximum mass of an object traveling at 479 m⋅s−1 for which the de broglie wavelength is observable, is 3.82×10⁻²⁷ kg.

Learn more about the De Broglie equation here;

https://brainly.com/question/19131384

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