pupj pupj
  • 02-01-2017
  • Mathematics
contestada

solve 3x+2y=4 4x+3y=7 algebraically

Respuesta :

xEngineerOrg
xEngineerOrg xEngineerOrg
  • 02-01-2017
Step 1. Multiply first equation with -3 and the second one with 2. You'll get:
[tex] \left \{ {{-9x-6y=-12} \atop {8x+6y=14}} \right. [/tex]

Step 2. Add both equations together. You'll get:
[tex]-x=2[/tex], which gives x = -2

Step 3. Replace x = -2 in the first equation and calculate y.
[tex]3(-2)+2y=4\\ y=\frac{4+6}{2}=5[/tex]

The solution is: x=-2, y=5
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(3x^2 + 2x -2) + ( -2x^2 + 5x+5) My answer 5x^2 + 7× +7 Am i right