Respuesta :

VectorFundament120

Answer:

f(6) = 320

Step-by-step explanation:

This is similar to Recurrence Relation;

First off, let's find f(2)

  • f(2) = 2f(2-1) = 2f(1) = 2•10 = 20

Then find f(3) up to f(6)

  • f(3) = 2f(3-1) = 2f(2) = 2•20 = 40
  • f(4) = 2f(4-1) = 2f(3) = 2•40 = 80
  • f(5) = 2f(5-1) = 2f(4) = 2•80 = 160
  • f(6) = 2f(6-1) = 2f(5) = 2•160 = 320

Thus, f(6) is 320

Otras preguntas