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When the following equation is balanced with the lowest whole number coefficients possible, what is the coefficient in front of naoh? naoh h3po4 yields h2o na3po4 1 2 3 4

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antonsandiego
It looks like you are talking about this equation :
NaOH + H3PO4 ----> H2O + Na3PO4
If so, the the coefficient in front of naoh should be  3 acording to the balanced form of this equation [tex] 3 NaOH + H3PO4 ----\ \textgreater \ 3 H2O + Na3PO4 [/tex]

Answer: Option (c) is the correct answer.

Explanation:

An equation will be balanced when both number of reactants and products are equal.

The given equation is as follows.

  [tex]NaOH + H_{3}PO_{4} \rightarrow H_{2}O + Na_{3}PO_{4}[/tex]

Number of reactants are as follows.

  • Na = 1
  • O = 5
  • H = 4
  • P = 1

Number of reactants are as follows.

  • Na = 3
  • O = 5
  • H = 2
  • P = 1

To balance the equation, multiply NaOH on the reactant side by 3 and [tex]H_{2}O[/tex] on the product side by 3.

Therefore, the equation will be as follows.

[tex]3NaOH + H_{3}PO_{4} \rightarrow 3H_{2}O + Na_{3}PO_{4}[/tex]

The coefficient in front of NaOH is 3.