Jel14
Jel14
01-09-2014
Mathematics
contestada
how do you solve m/9 divided by mn squared / 3
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luana
luana
01-09-2014
[tex] To\ divide\ fraction\ multiply\ first\ fraction\ by\ inverse\ of\ the\ second:\\\\ \frac{m}{9}:\frac{mn^2}{3}=\frac{m}{9}*\frac{3}{mn^2}=\frac{1}{3n^2} \\\\Solution\ is \ \frac{1}{3n^2}.[/tex]
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Lilith
Lilith
01-09-2014
[tex]\frac{m}{9}:\frac{mn^2}{3} =\frac{m}{9} \cdot \frac{3}{mn^2} =\frac{1}{3n^2}[/tex]
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