Respuesta :

abscisa15

[tex]\it m(\widehat{DCA}) = m(\widehat{CBA}) +m(\widehat{BAC}) \Rightarrow m(\widehat{DCA}) \ \textgreater \ m(\widehat{CBA}) \Rightarrow \\ \\ \Rightarrow m(\widehat{DCA}) \ \textgreater \ 40^o [/tex]

So, we  choose: B) 70°